28x^2-5=-5x^2+127

Solution for 28x^2-5=-5x^2+127 equation:

28x^2-5=-5x^2+127

We move all terms to the left:

28x^2-5-(-5x^2+127)=0

We get rid of parentheses

28x^2+5x^2-127-5=0

We add all the numbers together, and all the variables

33x^2-132=0

a = 33; b = 0; c = -132;
Δ = b2-4ac
Δ = 02-4·33·(-132)
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{17424}=132$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-132}{2*33}=\frac{-132}{66}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+132}{2*33}=\frac{132}{66}
=2
$